Home php Star Rating System in jQuery PHP MYSQL

Star Rating System in jQuery PHP MYSQL

4 min read
0
1
6,969

This tutorial will teach you how to make Star Rating System in jQuery PHP MYSQL. The rating management system is made to rate an individual’s skillset accordingly.

Database connection

db_connection.php

<?php


$servername = "localhost";//Server Name
$username = "root";//Server User Name
$password = "";//Server Password
$dbname = "billdb";//Database Name

//Create DB Connection
$conn = mysqli_connect($servername,$username,$password,$dbname);

?>

 

add_rate.php

<html>
<head>
    <link rel="stylesheet" href="https://stackpath.bootstrapcdn.com/bootstrap/4.4.0/css/bootstrap.min.css" integrity="sha384-SI27wrMjH3ZZ89r4o+fGIJtnzkAnFs3E4qz9DIYioCQ5l9Rd/7UAa8DHcaL8jkWt" crossorigin="anonymous">
    <link rel="stylesheet" href="https://cdnjs.cloudflare.com/ajax/libs/rateYo/2.3.2/jquery.rateyo.min.css">
</head>
<body>
<div class="container">
    <div class="row">

<form action="add_rate.php" method="post">

    <div>
        <h3>Student Rating System</h3>
    </div>

    <div>
         <label>Name</label>
        <input type="text" name="name">
    </div>

         <div class="rateyo" id= "rating"
         data-rateyo-rating="4"
         data-rateyo-num-stars="5"
         data-rateyo-score="3">
         </div>

    <span class='result'>0</span>
    <input type="hidden" name="rating">

    </div>

    <div><input type="submit" name="add"> </div>

</form>
</div>
</div>
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<script src="https://cdnjs.cloudflare.com/ajax/libs/rateYo/2.3.2/jquery.rateyo.min.js"></script>

<script>


    $(function () {
        $(".rateyo").rateYo().on("rateyo.change", function (e, data) {
            var rating = data.rating;
            $(this).parent().find('.score').text('score :'+ $(this).attr('data-rateyo-score'));
            $(this).parent().find('.result').text('rating :'+ rating);
            $(this).parent().find('input[name=rating]').val(rating); //add rating value to input field
        });
    });

</script>
</body>

</html>
<?php
require 'db_connection.php';
if ($_SERVER["REQUEST_METHOD"] == "POST")
{
    $name = $_POST["name"];
    $rating = $_POST["rating"];

    $sql = "INSERT INTO ratee (name,rate) VALUES ('$name','$rating')";
    if (mysqli_query($conn, $sql))
    {
        echo "New Rate addedddd successfully";
    }
    else
    {
        echo "Error: " . $sql . "<br>" . mysqli_error($conn);
    }
    mysqli_close($conn);
}
?>

i have attached the video link below. which will do this tutorials step by step.

Load More Related Articles
Load More By admin
Load More In php

Leave a Reply

Your email address will not be published. Required fields are marked *

Check Also

Library Management System using Spring Boot

This tutorils will teach about complete library management project.the purpose of this pro…